(1/3)^(6x+5)=9x-2

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Solution for (1/3)^(6x+5)=9x-2 equation: 



(1/3)^(6x+5)=9x-2

We move all terms to the left:

(1/3)^(6x+5)-(9x-2)=0



Domain of the equation: 3)^(6x+5)!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)^(6x+5)-(9x-2)=0

We get rid of parentheses

(+1/3)^(6x+5)-9x+2=0

We multiply all the terms by the denominator


(+1-9x*3)^(6x+5)+2*3)^(6x+5)=0

We add all the numbers together, and all the variables

(-9x*3+1)^(6x+5)+2*3)^(6x+5)=0

We add all the numbers together, and all the variables

(-9x*3+1)^(6x+5)+2*3)^(6x=0

Wy multiply elements

(-9x*3+1)^(6x+5)+6x=0

We add all the numbers together, and all the variables

6x+(-9x*3+1)^(6x+5)=0

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